Direct Integrals of Von Neumann Algebras
Let {Hx}x ∈ X be a measurable family of Hilbert spaces. A family of von Neumann algebras {Ax}x ∈ X with
is measurable if and only if there is a countable set D of measurable operator families that pointwise generate {Ax} x ∈ Xas a von Neumann algebra in the following sense: For almost all x ∈ X,
where W*(S) denotes the von Neumann algebra generated by the set S. If {Ax}x ∈ X is a measurable family of von Neumann algebras, the direct integral of von Neumann algebras
consists of all operators of the form
for Tx ∈ Ax.
One of the main theorems of von Neumann and Murray in their original series of papers is a proof of the decomposition theorem: Any von Neumann algebra is a direct integral of factors. We state this precisely below.
Theorem. If {Ax}x ∈ X is a measurable family of von Neumann algebras and μ is standard, then the family of operator commutants is also measurable and
Read more about this topic: Direct Integral
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