Burnside Ring - Marks

Much like character theory simplifies working with group representations, marks simplify working with permutation representations and the Burnside ring.

If G acts on X, and HG (H is a subgroup of G), then the mark of H on X is the number of elements of X that are fixed by every element of H:, where

If H and K are conjugate subgroups, then mX(H) = mX(K) for any finite G-set X; indeed, if K = gHg−1 then XK = g · XH.

It is also easy to see that for each HG, the map Ω(G) → Z : XmX(H) is a homomorphism. This means that to know the marks of G, it is sufficient to evaluate them on the generators of Ω(G), viz. the orbits G/H.

For each pair of subgroups H,KG define

This is mX(H) for X = G/K. The condition HgK = gK is equivalent to g−1HgK, so if H is not conjugate to a subgroup of K then m(K, H) = 0.

To record all possible marks, one forms a table, Burnside's Table of Marks, as follows: Let G1 (= trivial subgroup), G2, ..., GN = G be representatives of the N conjugacy classes of subgroups of G, ordered in such a way that whenever Gi is conjugate to a subgroup of Gj, then ij. Now define the N × N table (square matrix) whose (i, j)th entry is m(Gi, Gj). This matrix is lower triangular, and the elements on the diagonal are non-zero so it is invertible.

It follows that if X is a G-set, and u its row vector of marks, so ui = mX(Gi), then X decomposes as a disjoint union of ai copies of the orbit of type Gi, where the vector a satisfies,

aM = u,

where M is the matrix of the table of marks. This theorem is due to (Burnside 1897).

Read more about this topic:  Burnside Ring

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