Examples For Consequences of The Formula
By maximizing B(A,Z) with respect to Z, we find the number of protons Z of the stable nucleus of atomic weight A. We get
This is roughly A/2 for light nuclei, but for heavy nuclei there is an even better agreement with nature.
By substituting the above value of Z back into B one obtains the binding energy as a function of the atomic weight, B(A). Maximizing B(A)/A with respect to A gives the nucleus which is most strongly bound, i.e. most stable. The value we get is A=63 (copper), close to the measured values of A=62 (nickel) and A=58 (iron).
Read more about this topic: Semi-empirical Mass Formula
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