Chemical Equation
The reactions involved are as follows:
- Na2S2O5 + H2O → 2 NaHSO3
- IO3- + 3 HSO3- → I- + 3 SO42- + 3 H+
This reaction reduces iodate ions to iodide ions. - Hg2+ + 2 I- → HgI2
Orange mercury iodide solid is precipitated until the mercury is used up. - IO3- + 5 I- + 6 H+ → 3 I2 + 3 H2O
The excess I- and IO3- undergo the iodide-iodate reaction - I2 + starch → a blue/black complex
A blue/black starch-iodine complex is formed.
Read more about this topic: Old Nassau Reaction
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