Nolot - Problem 9

Problem 9

FEN r4r1k/4bppb/2n1p2p/p1n1P3/1p1p1BNP/3P1NP1/qP2QPB1/2RR2K1 w - - 0 1

Problem 9
Weinstein - Elyoseph, Israel 1992

	a	b	c	d	e	f	g	h
8									8
7									7
6									6
5									5
4									4
3									3
2									2
1									1
	a	b	c	d	e	f	g	h

White to play: Ng5!!

1.Ng5!! hxg5 2.hxg5! (with the idea of 3. Nf6!!) and now:

A. 2...Rac8 3.Nf6!!

A1. 3...gxf6 which loses if white play precisely: 4.gxf6 and now:

A1a. 4...Nxd3? 5.Rxd3 Bxd3? 6.Qh5+ is mate in 4.

A1b. 4...Re8 5.Rxc5! (5.Qh5!? Kg8 6.Rxc5! Bg6! 7.Qh4 Bxc5 8.Be4 Ne7 9.Kg2! is winning as well.) 5...Bxc5 6.Qh5 with the idea 7.Be4 and White is winning.

A1c. 4...Bg6 5.Bxc6 Bxf6 (6...Rxc6 6.fxe7 Re8 7.Bg5 f5 8.Bf6+ Kg8 9.Qd2 is winning) 7.Rxc5 Be7 8.Rcc1 and White is better.

A2. 3...Nb8 4.Bd5!! (to block d5 so White can play Kg2 without having to deal with ...Qd5+; 4.Qh5!? Bxf6 5.gxf6 Nbd7 (5...gxf6 6.Rxc5! Rxc5 7.Be4 f5 8.Kg2! Rg8 9.Rh1 Rg7 10.Bh6 Nd7 11.Bxg7+ Kxg7 12.Qxh7+ Kf8 13.Qh6+ Ke8 14.Qg5 is winning.) 6.Bb7 Nxb7 7.Rxc8 Rxc8 8.Qxf7 Rg8 9.Qxd7 with advantage for White.) 4...exd5 (4...Qxd5 5.Nxd5 exd5 6.Kg2! should win as well.) 5.Kg2! Bxf6 6.Rh1! Bg5 7.Qh5 Bh6 8.Bxh6 with mate to follow.

B. 2...Rfc8 3.Nf6!!

B1. 3...gxf6 4.exf6! (4.gxf6 Nxd3 (4...Bf8 5.Rxc5! Bxc5 6.Qh5 Kg8 7.Be4 Bxe4 8.dxe4 wins for White.) 5.Rxd3 Bxd3 6.Qxd3 Nxe5! 7.Rxc8+ Rxc8 8.Bxe5 Qa1+ is unclear, probably a draw.) and now:

B1a. 4...Bf8? 5.Rxc5! Bxc5 6.Qh5 Kg8 7.Be4 Bxe4 8.dxe4 is winning for White, e.g. 8...Qa4 9.Rc1 Ne7 10.fxe7 Qe8 11.Kg2! f6 12.Qh6.

B1b. 4...Nxd3 5. Rxd3 Bf8! (6...Bxd3 6. Qxd3 wins for White.) 6.Rxc6 (6.Bxc6!? Rxc6 7.Rxc6 Qd5 8.Rc7 is better for White.) 6...Rxc6 7.Bxc6 Rd8 8.Rd1 is also favorable for White.

B2. 3...Bg6 is probably Black's best try:

B2a. 4.Bxc6 gxf6 5.exf6 Bf8! 6.Bxa8 Rxa8 7.Rc4 and Black seems to hold.

B2b. 4.Qg4 gxf6 5.gxf6 Nxd3 (5...Bf8? 6.Qh3+ Kg8 7.Bh6! is winning) 6.Rxd3 Bf8 7.Rdd1 is unclear.

Pierre Nolot seems to have repudiated this problem.