Lexicographical Order - Case of Multiple Products

Case of Multiple Products

Suppose

\{ A_1, A_2, \cdots, A_n \}

is an n-tuple of sets, with respective total orderings

\{ <_1, <_2, \cdots, <_n \}

The dictionary ordering

\ \ <^{d}

of

A_1 \times A_2 \times \cdots \times A_n

is then

(a_1, a_2, \dots, a_n) <^d (b_1,b_2, \dots, b_n) \iff (\exists\ m > 0) \ (\forall\ i < m) (a_i = b_i) \land (a_m <_m b_m)

That is, if one of the terms

\ \ a_m <_m b_m

and all the preceding terms are equal.

Informally,

\ \ a_1

represents the first letter,

\ \ a_2

the second and so on when looking up a word in a dictionary, hence the name.

This could be more elegantly stated by recursively defining the ordering of any set

\ \ C= A_j \times A_{j+1} \times \cdots \times A_k

represented by

\ \ <^d (C)

This will satisfy

a <^d (A_i) a' \iff (a <_i a')
(a,b) <^d (A_i \times B) (a',b') \iff a <^d (A_i) a' \lor ( a=a' \ \land \ b <^d (B) b')

where B = A_{i+1} \times A_{i+2} \times \cdots \times A_n.

To put it more simply, compare the first terms. If they are equal, compare the second terms – and so on. The relationship between the first corresponding terms that are not equal determines the relationship between the entire elements.

Read more about this topic:  Lexicographical Order

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