Digamma Function - Recurrence Formula and Characterization

Recurrence Formula and Characterization

The digamma function satisfies the recurrence relation

(see proof)


Thus, it can be said to "telescope" 1/x, for one has

where Δ is the forward difference operator. This satisfies the recurrence relation of a partial sum of the harmonic series, thus implying the formula

where is the Euler-Mascheroni constant.

More generally, one has

\psi(x+1) = -\gamma + \sum_{k=1}^\infty
\left( \frac{1}{k}-\frac{1}{x+k} \right).

Actually, is the only solution of the functional equation that is monotone on and satisfies . This fact follows immediately from the uniqueness of the function given its recurrence equation and convexity-restriction.

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