Central Carrier - Related Results

Related Results

One can deduce some simple consequences from the above description. Suppose E and F are projections in a von Neumann algebra M.

Proposition ETF = 0 for all T in M if and only if C(E) and C(F) are orthogonal, i.e. C(E)C(F) = 0.

Proof:

ETF = 0 for all T in M.
⇔ ⊂ Ker(E).
C(F) ≤ 1 - E, by the discussion in the preceding section, where 1 is the unit in M.
E ≤ 1 - C(F).
C(E) ≤ 1 - C(F), since 1 - C(F) is a central projection that dominates E.
This proves the claim.

In turn, the following is true:

Corollary Two projections E and F in a von Neumann algebra M contain two nonzero subprojections that are Murray-von Neumann equivalent if C(E)C(F) ≠ 0.

Proof:

C(E)C(F) ≠ 0.
ETF ≠ 0 for some T in M.
ETF has polar decomposition UH for some partial isometry U and positive operator H in M.
Ran(U) = Ran(ETF) ⊂ Ran(E). Also, Ker(U) = Ran(H)⊥ = Ran(ETF)⊥ = Ker(ET*F) ⊃ Ker(F); therefore Ker(U))⊥ ⊂ Ran(F).
⇒ The two equivalent projections UU* and U*U satisfy UU*E and U*UF.

In particular, when M is a factor, then there exists a partial isometry UM such that UU*E and U*UF. Using this fact and a maximality argument, it can be deduced that the Murray-von Neumann partial order « on the family of projections in M becomes a total order if M is a factor.

Proposition (Comparability) If M is a factor, and E, FM are projections, then either E « F or F « E.

Proof:

Let ~ denote the Murray-von Neumann equivalence relation. Consider the family S whose typical element is a set { (Ei, Fi) } where the orthogonal sets {Ei} and {Fi} satisfy EiE, FiF, and Ei ~ Fi. The family S is partially ordered by inclusion and the above corollary shows it is non-empty. Zorn's lemma ensures the existence of a maximal element { (Ej, Fj) }. Maximality ensures that either E = ∑ Ej or F = ∑ Fj. The countable additivity of ~ means Ej ~ ∑ Fj. Thus the proposition holds.

Without the assumption that M is a factor, we have:

Proposition (Generalized Comparability) If M is a von Neumann algebra, and E, FM are projections, then there exists a central projection PZ(M) such that either EP « FP and F(1 - P) « E(1 - P).

Proof:

Let S be the same as in the previous proposition and again consider a maximal element { (Ej, Fj) }. Let R and S denote the "remainders": R = E - ∑ Ej and S = F - ∑ Fj. By maximality and the corollary, RTS = 0 for all T in M. So C(R)C(S) = 0. In particular R · C(S) = 0 and S · C(S) = 0. So multiplication by C(S) removes the remainder R from E while leaving S in F. More precisely, E · C(S) = (∑ Ej + R) · C(S) = (∑ Ej) · C(S) ~ (∑ Fj) · C(S) ≤ (∑ Fj + S) · C(S) = F · C(S). This shows that C(S) is the central projection with the desired properties.

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