Linear Polymers: Two Monomers in Equimolar Quantities
The simplest case refers to the formation of a strictly linear polymer by the reaction (usually by condensation) of two monomers in equimolar quantities. An example is the synthesis of nylon-6,6 whose formula is n from one mole of hexamethylenediamine, H2N(CH2)6NH2, and one mole of adipic acid, HOOC-(CH2)4-COOH. For this case
In this equation
-
- Xn is the number-average value of the degree of polymerization, equal to the average number of monomer units in a polymer molecule.
For the example of nylon-6,6 Xn = 2n (n diamine units and n diacid units). - p is the extent of reaction (or conversion to polymer), defined by
-
- p = (N0-N)/N0, where:
- N0 is the number of molecules present initially
- N is the number of unreacted molecules at time t
- Xn is the number-average value of the degree of polymerization, equal to the average number of monomer units in a polymer molecule.
This equation shows that a high monomer conversion is required to achieve a high degree of polymerization. For example, a monomer conversion, p, of 98% is required for Xn = 50, and p = 99% is required for Xn = 100.
Read more about this topic: Carothers Equation
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