6-j Symbol - Special Case

Special Case

When j₆ = 0 the expression for the 6-j symbol is:

$\begin{Bmatrix} j_1 & j_2 & j_3\\ j_4 & j_5 & 0 \end{Bmatrix} = \frac{\delta_{j_2,j_4}\delta_{j_1,j_5}}{\sqrt{(2j_1+1)(2j_2+1)}} (-1)^{j_1+j_2+j_3}\{j_1,j_2,j_3\}.$

The function {j₁, j₂, j₃} is equal to 1 when the triad (j₁, j₂, j₃) satisfies the triangle conditions, and zero otherwise. The symmetry relations can be used to find the expression when another j is equal to zero.

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