Stress Transformation in Plane Stress and Plane Strain
Consider a point in a continuum under a state of plane stress, or plane strain, with stress components and all other stress components equal to zero (Figure 7.1, Figure 8.1). From static equilibrium of an infinitesimal material element at (Figure 8.2), the normal stress and the shear stress on any plane perpendicular to the - plane passing through with a unit vector making an angle of with the horizontal, i.e. is the direction cosine in the direction, is given by:
These equations indicate that in a plane stress or plane strain condition, one can determine the stress components at a point on all directions, i.e. as a function of, if one knows the stress components on any two perpendicular directions at that point. It is important to remember that we are considering a unit area of the infinitesimal element in the direction parallel to the - plane.
The principal directions (Figure 8.3), i.e. orientation of the planes where the shear stress components are zero, can be obtained by making the previous equation for the shear stress equal to zero. Thus we have:
and we obtain
This equation defines two values which are apart (Figure 8.3). The same result can be obtained by finding the angle which makes the normal stress a maximum, i.e.
The principal stresses and, or minimum and maximum normal stresses and, respectively, can then be obtained by replacing both values of into the previous equation for . This can be achieved by rearranging the equations for and, first transposing the first term in the first equation and squaring both sides of each of the equations then adding them. Thus we have
where
which is the equation of a circle of radius centered at a point with coordinates, called Mohr's circle. But knowing that for the principal stresses the shear stress, then we obtain from this equation:
When the infinitesimal element is oriented in the direction of the principal planes, thus the stresses acting on the rectangular element are principal stresses: and . Then the normal stress and shear stress as a function of the principal stresses can be determined by making . Thus we have
Then the maximum shear stress occurs when, i.e. (Figure 8.3):
Then the minimum shear stress occurs when, i.e. (Figure 8.3):
Read more about this topic: Stress Analysis
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“with the plane nowhere and her body taking by the throat
The undying cry of the void falling living beginning to be something
That no one has ever been and lived through screaming without enough air”
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“That strain again, it had a dying fall;
O, it came oer my ear like the sweet sound
That breathes upon a bank of violets,
Stealing and giving odor. Enough, no more,
Tis not so sweet now as it was before.”
—William Shakespeare (15641616)
