Geography
Sabina is located at 39°29′21″N 83°38′6″W / 39.48917°N 83.635°W / 39.48917; -83.635 (39.489243, -83.635079), along Routes 22 and 3 about ten miles east of Wilmington, the county seat. It is also located within an hour's drive from the Columbus, Dayton, and Cincinnati metro areas.
According to the United States Census Bureau, the village has a total area of 1.3 square miles (3.4 km2), all of it land.
Sabina is located 31 miles south of Springfield and 47 miles southwest of Columbus.
Read more about this topic: Sabina, Ohio
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