Example
The figure shows a RC series circuit and the table shows the BCE of a linear resistor and a linear Capacitor. Note that in the case of the resistor the admittance i, is used instead of . We now proceed as explained above.
| Element | Branch equation |
|---|---|
| Resistor | |
| Capacitor |
Step 1
In this case there are two nodes, and . Also there are three currents:, and .
At node e1 the KCL yields:
and at node e2:
Step 2
With the provided BCEs in the table and observing that:
the following equations are result:
Step 3
Note that at this point there are two equations but three unknowns. The missing equation comes from the fact that
and so finally we have three equations and unknowns, what leads to a solvable linear system.
Read more about this topic: Modified Nodal Analysis
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