Magic Hyperbeam - Qualification

Qualification

Qualifying the hyperbeam is less developed then it is on the magic hypercubes in fact only the k'th monagonal direction need to sum to:

Sk = mk (j=0∏n-1mj - 1) / 2

for all k = 0..n-1 for the hyperbeam to be qualified {magic}

When the orders are not relatively prime the n-agonal sum can be restricted to:

S = lcm(mi ; i = 0..n-1) (j=0∏n-1mj - 1) / 2

with all orders relatively prime this reaches its maximum:

Smax = j=0∏n-1mj (j=0∏n-1mj - 1) / 2

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