Dqo Transformation - Comparison With Other Transforms - Park's Transformation

Park's Transformation

The transformation originally proposed by Park differs slightly from the one given above. Park's transformation is:

P= \frac{2}{3}\begin{bmatrix} \cos(\theta)&\cos(\theta - \frac{2\pi}{3})&\cos(\theta + \frac{2\pi}{3}) \\ \sin(\theta)&\sin(\theta - \frac{2\pi}{3})&\sin(\theta + \frac{2\pi}{3}) \\ \frac{1}{2}&\frac{1}{2}&\frac{1}{2} \end{bmatrix}

and

P^{-1} = \begin{bmatrix}\cos(\theta)&\sin(\theta)&1\\ \cos(\theta - \frac{2\pi}{3})&\sin(\theta - \frac{2\pi}{3})&1\\ \cos(\theta + \frac{2\pi}{3})&\sin(\theta + \frac{2\pi}{3})&1\end{bmatrix}

Although useful, Park's transformation is not power invariant whereas the dqo transformation defined above is. Park's transformation gives the same zero component as the method of symmetrical components. The dqo transform shown above gives a zero component which is larger than that of Park or symmetrical components by a factor of .

Read more about this topic:  Dqo Transformation, Comparison With Other Transforms

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