Geography
Ashtabula is located at 41°52′38″N 80°47′49″W / 41.87722°N 80.79694°W / 41.87722; -80.79694 (41.877138, -80.796976).
According to the 2010 census, the city has a total area of 7.91 square miles (20.5 km2), of which 7.74 square miles (20.0 km2) (or 97.85%) is land and 0.17 square miles (0.44 km2) (or 2.15%) is water.
Ashtabula borders Lake Erie to the north and has a prominent harbor where the Ashtabula River flows into the lake. The Ashtabula Harbor was a primary coal harbor and still serves to ship . It has two public beaches: Walnut Beach, near the harbor, and Lake Shore Park, originally a Public Works Administration project, on the opposite side of the harbor.
The Ashtabula River and harbor are a significant superfund site due to past industrial abuse of the waterway.
Part of the city lies in Ashtabula Township, and part lies in Saybrook Township.
The Ashtabula area receives a considerable amount of snow throughout the winter with the average snowfall being 68 inches. Much of the snow comes from lake-effect snow bands.
Read more about this topic: Ashtabula, Ohio
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