1978 NBA Playoffs - Western Conference

Western Conference

Champion: Seattle SuperSonics

1st Round

(1) Portland Trail Blazers and (2) Denver Nuggets have first-round byes.

(3) Phoenix Suns vs. (6) Milwaukee Bucks: Bucks win series 2-0

  • Game 1 @ Phoenix: Milwaukee 111, Phoenix 103
  • Game 2 @ Milwaukee: Milwaukee 94, Phoenix 90

(4) Seattle SuperSonics vs. (5) Los Angeles Lakers: Sonics win series 2-1

  • Game 1 @ Seattle: Seattle 102, Los Angeles 90
  • Game 2 @ Los Angeles: Los Angeles 105, Seattle 99
  • Game 3 @ Seattle: Seattle 111, Los Angeles 102

Conference Semifinals

(1) Portland Trail Blazers vs. (4) Seattle SuperSonics: Sonics win series 4-2

  • Game 1 @ Portland: Seattle 104, Portland 95
  • Game 2 @ Portland: Portland 96, Seattle 93
  • Game 3 @ Seattle: Seattle 99, Portland 84
  • Game 4 @ Seattle: Seattle 100, Portland 98
  • Game 5 @ Portland: Portland 113, Seattle 89
  • Game 6 @ Seattle: Seattle 105, Portland 94

(2) Denver Nuggets vs. (6) Milwaukee Bucks: Nuggets win series 4-3

  • Game 1 @ Denver: Denver 119, Milwaukee 103
  • Game 2 @ Denver: Denver 127, Milwaukee 111
  • Game 3 @ Milwaukee: Milwaukee 143, Denver 112
  • Game 4 @ Milwaukee: Denver 118, Milwaukee 114
  • Game 5 @ Denver: Milwaukee 117, Denver 112
  • Game 6 @ Milwaukee: Milwaukee 119, Denver 91
  • Game 7 @ Denver: Denver 116, Milwaukee 110

Conference Finals

(2) Denver Nuggets vs. (4) Seattle SuperSonics: Sonics win series 4-2

  • Game 1 @ Denver: Denver 116, Seattle 107
  • Game 2 @ Denver: Seattle 121, Denver 111
  • Game 3 @ Seattle: Seattle 105, Denver 91
  • Game 4 @ Seattle: Seattle 100, Denver 94
  • Game 5 @ Seattle: Denver 123, Seattle 114
  • Game 6 @ Denver: Seattle 123, Denver 108

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